Question 1205018



let’s three odd consecutive integers be  {{{x}}}, {{{x+2}}}, and {{{x+4}}}

if the sum of quadruple the largest and twice the smallest is {{{46}}}, we have

{{{4(x+4)+2x=46}}}...simplify, both sides divide by {{{2}}}

{{{2(x+4)+x=23}}}

{{{2x+8+x=23}}}

{{{3x=23-8}}}

{{{3x=15}}}

{{{x=5}}}

integers are: {{{5}}},{{{ 7}}},{{{9}}}


check 

{{{4(x+4)+2x=46}}}

{{{4(9)+2*5=46}}}

{{{36+10=46}}}

{{{46=46}}}