Question 1204993
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I'm assuming the 1/2x should be (1/2)x.
I'll rewrite that as x/2.


g(x) = f(x/2)


The question is: what can we plug into g(x) to land on the known value f(x) = -4?


If we tried x = -1, then we'll get
g(x) = f(x/2)
g(-1) = f(-1/2)
That's no good because we don't know what f(-1/2) is.


But what if we tried x = -2
g(x) = f(x/2)
g(-2) = f(-2/2)
g(-2) = f(-1)
g(-2) = -4
So as you can see, the idea is to set the x/2 equal to the previous x value -1. Solving x/2 = -1 for x gets us the new input x = -2.


Since g(-2) = -4, we know that (-2,-4) is on g(x).


An example:
{{{
drawing(400,400,-5,5,-5,5,
graph(400,400,-5,5,-5,5,-100,4x,2x),

circle(-1,-4,0.05),circle(-1,-4,0.07),circle(-1,-4,0.09),circle(-1,-4,0.11),circle(-1,-4,0.13),circle(-1,-4,0.15),circle(-2,-4,0.05),circle(-2,-4,0.07),circle(-2,-4,0.09),circle(-2,-4,0.11),circle(-2,-4,0.13),circle(-2,-4,0.15),

locate(1.5+0.2,-4.5,"(-1,-4)"),
locate(-2-1.8,-4+0.4,"(-2,-4)"),

line(1.5,-4.5,-0.8,-4.2),
line(-0.8,-4.2,-0.3236,-4.5647),
line(-0.8,-4.2,-0.246,-3.9697)
)
}}}
f(x) = 4x in green
g(x) = f(x/2) = 4(x/2) = 2x in blue
Use a graphing tool like GeoGebra or Desmos to try out other examples.


Replacing each input x with x/2 horizontally stretches the graph by a factor of 2. 
Function g(x) is twice as wide, so to speak, compared to f(x). 



Answer:  <font color=red size=4>(-2, -4)</font>
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