<PRE><B>Question 1204967</B>
Tony found four consecutive even integers such that 5 times the sum of the first and third was 9604 greater than twice the sum of the second and the fourth. Find the numbers and express each in standard form.



n-3, n-1,n+1,n+3


 5 times the sum of the first and third was 9604 greater than twice the sum of the second and the fourth. 

5(n-3+n+1)= 2(n-1+n+3)+9604

5(2n-2)=2(2n+2)+9604

10n-10 = 4n+4+9604

6n = 9618

n= 1603

n-3= 1603-3= 1600

n-1= 1603-1= 1602

n+11603+1=1604

n+3= 1603+3- 1606

CHECK

5*(1600+1604)= 2(1602+1606)+9604 =16020


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