Question 115629
1. In ten years, Eric's age will be seventy-three less than four times the age of Alexander.
(E+10) = 4(A+10) - 73
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2. Kevin is sixty-three years younger than Jonathan.
K = J - 63
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3. Elizabeth is forty-one years older than Kevin.
E = K + 41
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4. The sum of of the ages of Elizabeth and Kevin is sixty-seven.
E + K = 67
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5. Eric's age is sixteen less than three times the age of Alexander. 
E = 3A - 16
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#3: E-K=41
#4: E+K=67
Add to get:2E = 108
E = 54 years old
K = 13 years old
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#5: E =3A-16
But E = 54
54 = 3A-16
3A = 70
A = 70/3 years old
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#1: (E+10) = 4(A+10) - 73
(54+10) = 4A+40 - 73
64 = 4A+40 - 73
4A = 97
A = 97/4
Comment: Result contradicts A = 70/3
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Cheers,
Stan H.