Question 1204953
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<pre>

You can select 7 persons to one group from 14 persons in  {{{C[14]^7}}} = {{{(14*13*12*11*10*9*8)/(1*2*3*4*5*6*7)}}} = 3432 different ways.   <U>ANSWER</U>


As soon as you select 7 persons from 14 for one group,
the second group is formed AUTOMATICALLY from the rest of people.


So, the number of ways to form two groups of 7 from 14 people is the same, 
as the number of ways to form two groups of 7 each from 14 people.


<U>ANSWER</U>.  3432 different ways.
</pre>

Solved.


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Since the order of persons does not matter, &nbsp;this problem is on &nbsp;COMBINATIONS.


On &nbsp;Combinations, &nbsp;see introductory lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =http://www.algebra.com/algebra/homework/Permutations/Introduction-to-Combinations-.lesson>Introduction to Combinations</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =http://www.algebra.com/algebra/homework/Permutations/PROOF-of-the-formula-on-the-number-of-combinations.lesson>PROOF of the formula on the number of Combinations</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =http://www.algebra.com/algebra/homework/Permutations/Problems-on-Combinations.lesson>Problems on Combinations</A>

in this site.


Learn the subject from there.