Question 1204945
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First a typical formal algebraic setup and solution....<br>
Let x = sister's age
then x+10 = Zoron's age
x+3 = sister's age in three years
(x+10)+3 = x+13 = Zoron's age in three years<br>
Zoron's age in three years will be twice his sister's age then:<br>
x+13 = 2(x+3)
x+13 = 2x+6
7 = x<br>
ANSWERS:
Zoron's age now: x+10 = 17
sister's age now: x = 7<br>
And now a less traditional and less formal solution, using logical reasoning....<br>
The difference in their ages is 10 years, so when he is twice as old as his sister, their ages will be 10 and 20.  That will be 3 years from now, so their ages now are 7 and 17.<br>
ANSWERS (again): 7 and 17<br>