Question 1204938
.
a rocket is moving vertically upward at a speed of 245 meters per second 
when its fuel runs out. how much farther will it start to travel upward 
before starting fall back to the ground.
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<pre>
Write equation relevant to this problem

    h(t) = -10*t^2 + 245t + {{{h[0]}}}.


Here h(t) is the current height, t is the time, counted from the moment, 
when the fuel stopped running;  {{{h[0]}}} is the height, where the fuel stop running.


From this equation, find the time {{{t[max]}}} for the maximum height

    {{{t[max]}}} = " {{{-b/(2a) }}} " = {{{-245/((2*(-10)))}}} = {{{245/20}}} = 12.25 seconds.


Now 

    "how much farther" = -10*12.25^2 + 245*12.25 = 1500.625 meters.    <U>ANSWER</U>
</pre>


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