Question 1204929




given point:

({{{2}}}, {{{2}}})

convert to polar coordinates with

{{{r > 0}}}, {{{0 <= theta <= 2pi}}}


find {{{r}}} using formula:

{{{r=sqrt(x^2+y^2)}}}

{{{r=sqrt(2^2+2^2)}}}

{{{r=sqrt(2*2^2)}}}

{{{r=2sqrt(2)}}}



{{{theta=tan^-1(y/x)}}}

{{{theta=tan^-1(2/2)}}}

{{{theta=tan^-1(1)}}}

{{{theta=pi/4}}}


since given point is in {{{Q }}}{{{I}}}, solution is {{{theta=pi/4}}} 


so, polar coordinates are ({{{r}}}, {{{theta}}})=({{{2sqrt(2)}}}, {{{pi/4}}})