Question 1204896
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A = (-2, -3)
B = (6, 1)


The horizontal gap from A to B is 8 units.
Use a number line to see there are 8 spaces between -2 and 6.
Or subtract and use absolute value: {{{abs(A-B) = abs(-2-6) = abs(-8) = 8}}} or {{{abs(B-A) = abs(6-(-2)) = abs(6+2) = abs(8) = 8}}}
Absolute value is needed since a negative distance isn't valid.


One quarter of this 8 unit horizontal gap is 8/4 = 2 units.
Let p = 2


The vertical gap from A to B is 4 units. 
One quarter of which is 4/4 = 1. 
Let q = 1.


When starting at A(-2,-3), move p = 2 units left and q = 1 unit down. 
This has us arrive at <font color=red>C(-4,-4)</font> as shown in the tutor @mananth's diagram


Now focus on point B(6,1)
We move p = 2 units right and q = 1 unit up to arrive at <font color=red>D(8,2)</font>. 
Refer to that same diagram.


In summary, segment AB extends out to CD such that
A = (-2, -3)
B = (6, 1)
<font color=red>C = (-4,-4)
D = (8,2)</font>
GeoGebra is a very useful tool to confirm the answers.


Side notes:
AB = 4*AC
AB = 4*BD
CD = (3/2)*AB
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