Question 1204913
<br>
[1] {{{3a+2b=2}}}<br>
{{{6a+2b=k-3a-mb}}}
[2] {{{9a+(2+m)b=k}}}<br>
Equation [1] is equivalent to<br>
[3] {{{9a+6b=6}}}<br>
There are an infinite number of solutions if [2] and [3] are equivalent.  That is true only if the coefficients of b in both equations are the same and the constants in both are the same.<br>
2+m = 6 --> m = 4
k = 6<br>
ANSWERS: k = 6; m = 4<br>