Question 1204856
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Let D be the midpoint of side BC.  Then the center of the circle O is on AD.<br>
Let E be on side AC such that OE is a radius of the circle.<br>
Triangles AEO and ADC are 30-60-90 right triangles.<br>
With AC = 22, DC = 11 and AD = 11*sqrt(3).<br>
And with OE = 5, AO = 10.<br>
The problem asks for the length of OD, which is AD - AO.<br>
ANSWER: 11*sqrt(3)-10<br>