Question 1204752
<pre>
If 6^(2x+1) = k, then 6^(4x+3) equals

A 12k
B k^2 + 6
C 6k^2
D 2k + 6
E 36k^2

{{{matrix(1,3, 6^(2x + 1), "=", k)}}}, then {{{matrix(1,3, 6^(4x + 3), "=", "?")}}}

{{{matrix(5,3, 6^(2x + 1), "=", k, 6^(2x) * 6^1, "=", k, 6^(2x), "=", k/6, (6^(2x))^2, "=", (k/6)^2, 6^(4x), "=", k^2/6^2)}}} 

                                  {{{matrix(1,3, 6^(4x + 3), "=", 6^(4x) * 6^3)}}}
                                            {{{(k^2/6^2)6^3}}} ----- Substituting {{{matrix(1,3, k^2/6^2, for, 6^(4x))}}}
                                           {{{highlight_green(matrix(1,5, (k^2/cross(6^2))6cross(6^3), "=", highlight(6k^2), "(CHOICE", "C)"))}}}</pre>