Question 1204835
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The sum of age's of a man and his daughter is 120years.
six years ago,the man's age was thrice that of his daughter.find their present age.
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Let x be the daughter's age, in years.

Then the the father's age is (120-x) years.


Six years ago

    ((120-x)-6) = 3*(x-6).


Simplify and find x

    114-x = 3x - 18

    114 + 18 = 3x + x

    132 = 4x

    132/4 = x

    x = 33.


The daughter's current age is 33 years.

The father's current age is 120-33 = 87 years.
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Solved.