Question 1204790
The stopping distance s of a car varies directly as the square of its speed v. If a car traveling at 30 mph requires 45 ft to stop, find the stopping distance for a car traveling at 45 mph.

{{{d(alpha)v^2}}}

d= kv^2

car traveling at 30 mph requires 45 ft to stop, 

45= k*(30)^2

k= 45/900= 1/20

 stopping distance for a car traveling at 45 mph.

d=k*v^2

d = (1/20)  * 45^2 

d=101.25 ft