Question 1204789
Area of triangle = 1

Area of triangle = 1/2 * base * height

2= b*h

b=2/h

h^2+(2/h)^2=2^2 (pythagoras theorem)

h^2 +4/h^2 = 4

h^2 +4/h^2 -4=0

h^4+4-4h^2=0

h^4-4h^2+4=0

(h^2-2)^2=0

h=sqrt(2)
b= 2/sqrt(2) = sqrt(2)

Perimeter= {{{sqrt(2)+sqrt(2)+2}}}

Perimeter ={{{2+2*sqrt(2)}}}

a^2+b^2=c^2
c=2  (hypotenuse)

{{{ sqrt(2)^2+sqrt(2)^2= 4}}}