Question 1204773
{{{(x+4)^2/3^2-(y+3/2)^2/(1/2)^2=1}}}


{{{(x+4)^2/9-(y+3/2)^2/(1/4)=1}}}


{{{(x+4)^2/9-4(y+3/2)^2=1}}}...both sides multiply by {{{9}}}


{{{(x+4)^2-36(y+3/2)^2=9}}}


{{{(x+4)^2-36(y^2 + 3y + 9/4)=9}}}


{{{x^2 + 8x - 36y^2 - 108y - 65=9}}}


{{{x^2 + 8x - 36y^2 - 108y - 65-9=0}}}


{{{x^2 + 8x - 36y^2 - 108y - 74=0}}} =>The general form is this



not this x^2 - 36y^2 + 8x - 108y - 90 = 0