Question 1204733
{{{2y^2 + 16x = 16y - 64}}}
Note the coefficients are multiples of 2.


{{{y^2+8x=8y-32}}}

{{{y^2-8y=-8x-32}}}

{{{y^2-8y+16=-8x-32+16}}}, trying Complete The Square

{{{(y-4)^2=-8x-16}}}

{{{(y-4)^2=-8(x+2)}}}
I stop right here; but you see clearly vertex is at  (-2,4).