Question 1204714
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p+2p = 3p+1
3p = 3p+1
0 = 1
In the last step, we subtract 3p from both sides
The last equation is a contradiction. 
It's never true regardless of what we select for p in the original equation.


Therefore, p+2p = 3p+1 has no solutions.
Other examples are possible such as p+3p = 4p+2 or 7p+5 = 3p+4p
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