Question 1204695
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Using formal algebra and the standard method for working the problem....<br>
{{{abs(y-12)=16}}}
{{{y-12=16}}} OR {{{y-12=-16}}}
{{{y=16+12=28}}} OR {{{y=-16+12=-4}}}<br>
ANSWERS: y=28 and y=-4<br>
In many problems involving absolute value, the work can be done informally, using the concept that "{{{abs(y-12)=16}}}" means the distance between y and 12 is 16.  That gives us, quickly,<br>
ANSWERS: 12+16 = 28 and 12-16 = -4<br>