Question 1204696
The general form of a hyperbola is 

{{{Ax^2 + Bx + Cy^2 + Dy + E = 0}}}

where either {{{A}}} or {{{C }}}is negative (but never both)

respecting alphabetic order, let say {{{A}}} is positive and {{{C}}} is negative

{{{Ax^2 + Bx -Cy^2 + Dy + E = 0}}}

in this case hyperbola opens up and down, just as in your case

{{{(y^2)/36 - (x^2)/16 = 1}}}....both sides multiply by {{{36*16}}} and you get

{{{16y^2- 36x^2 = 36*16}}}... simplify, divide by {{{4}}}

{{{4y^2- 9x^2 = 36*4}}}

{{{4y^2- 9x^2 -144=0}}}.... {{{A=-9}}}, to make it positive multiply equation by {{{-1}}}

{{{-4y^2+9x^2 +144=0}}}...rearrange

{{{9x^2 -4y^2+144=0}}}