Question 1204692
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x = cost of one saucer
x+7 = cost of one teapot
2x = cost of one cup


2x = cost of 2 saucers
2*2x = 4x = cost of 2 cups


(4x)+(2x)+(x+7) = cost of 2 cups, 2 saucers, and 1 teapot
(4x)+(2x)+(x+7) = 30.20


Let's solve for x
(4x)+(2x)+(x+7) = 30.20
4x+2x+x+7 = 30.20
7x+7 = 30.20
7x = 30.20-7
7x = 23.20
x = 23.20/7
x = 3.3142857 approximately
x = <font color=red size=4>3.31</font> is the cost of one saucer when rounding to the nearest cent
x+7 = 3.31 + 7 = <font color=red size=4>10.31</font> is the cost of one teapot
2x = 2*3.31 = <font color=red size=4>6.62</font> is the cost of one cup



Check:
2 cups + 2 saucers + 1 teapot = 2*6.62 + 2*3.31 + 10.31 = 30.17
which is somewhat close to the goal of 30.20
Things are off a bit because we went from 3.3142857 to 3.31


There might be a typo with one or more of the numbers given by the teacher. 
I recommend contacting your son's teacher for clarification.
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