Question 1204657


The girl is 4 years older than her brother and 22 years younger than her father.

Let father'sage be x and brother's age be y

y+4 =x-22

y-x= -26------------------1

 Five years ago their father was twice as old as the sum of the ages of the children. How old is the children and father?

(x-5)= 2(y-5 +y+4-5)

(x-5) = 2(2y-6)

4y-12=x-5 

4y-x= 7--------------------2

4y-x= 7
y-x= -26   we get
3y=33

y = 11 Brother's age

girl's age = y+4=15

x=37 father'age 


The children are 11 (brother) and 15 (girl), and the father is 37 years old