Question 1204627
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<pre>

In the post by @MathLover1, her answer to (a),  {{{sin(x/2)}}} = {{{-(5*sqrt(29))/29)}}}, is incorrect.

To determine the correct answer, we should analyze in which quadrant the angle {{{x/2}}} lies.

Since angle x is in QIII, we conclude that {{{x/2}}} lies in QII.

Hence,  {{{sin(x/2)}}}  must be POSITIVE  in this problem.

THEREFORE, the correct answer to (a) is  {{{sin(x/2)}}} = {{{(5*sqrt(29))/29)}}},

           the opposite number to the answer by @MathLover1.




Similarly, in her post, the answer to (c),  {{{tan(x/2)}}} = {{{5/2)}}}, is incorrect.

Again, the angle {{{x/2}}}  lies in QII, where  tangent is always negative.

THEREFORE, the correct answer to (c) is  {{{tan(x/2)}}} = {{{-5/2)}}},

           the opposite number to the answer by @MathLover1.
</pre>

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Hello, could you take care about your posts, in order for they come in good format ?


For it, you should STOP copy-paste from your source, since it does not work properly.


You should print your posts manually using your keyboard and supporting the rules of mathematical grammar.