Question 1204613


{{{sin(x+2pi/3)}}}= 

use identity

{{{sin((A+B))=cos(B) *sin(A) + cos(A)* sin(B)}}}


in your case {{{A=x}}} and {{{B=2pi/3}}}

{{{sin(x+2pi/3)= cos(2pi/3)* sin(x) + cos(x) *sin(2pi/3)}}}