Question 1204568
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A different approach -- easier, in my opinion...<br>
Use {{{log(a,(b))=log((b))/log((a))}}}<br>
For this problem, we have<br>
{{{log(9,(3sqrt(3)))=log((3sqrt(3)))/log((9))}}}<br>
In this expression we can use any base we want. Since all the numbers are powers of 3, use log base 3.<br>
{{{log(3,(3sqrt(3)))/log(3,(9))=1.5/2=3/4}}}<br>
ANSWER: 3/4<br>