Question 1204560


{{{28<=  2(4x+9)<5(x+7) <= 64}}}

first do

{{{28<=  2(4x+9)}}}

{{{28<=8x+18}}}

{{{28-18<=8x}}}

{{{10<=8x}}}

{{{10/8<=x}}}

{{{5/4<=x}}}


then do

{{{2(4x+9)<5(x+7)}}}

{{{8x+18<5x+35}}}

{{{8x-5x<-18+35}}}

{{{3x<17}}}

{{{x<17/3}}}


so we have

{{{ 5/4<=x<17/3 }}}

since all will be  <= {{{64}}}

solution is:

{{{5/4<=x<17/3 }}}