<PRE><B>Question 1204535</B>
p = perimeter
l = length
w = width
l = w + 52
p = 2l + 2w
replace l with w + 52 to get:
p = 2(w + 52) + 2w = 2w + 104 + 2w = 4w + 104
replace p with 296 to get:
296 = 4w + 104
subtract 104 from both sides of the equation to get:
192 = 4w
solve for w to get:
w = 192/4 = 48
l = w + 52 = 48 + 52 = 100
2l + 2w = 200 + 96 = 296
values of l and w look good.
solution is that the dimensions of the field ares 100 by 48.



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