Question 1204507
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Rachelle has $4.45 in dimes and nickles in her car. The number of nickles is twenty more 
than the number of dimes. How many of each type of coin does she have?
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        Good problem to solve it mentally and to train your mind.



<pre>
Put twenty extra nickels aside, for a minute.


Then the remaining collection consists of equal number of nickels and dimes
and is worth 445 - 5*20 = 345 cents.


One nickel PLUS one dime are worth 5+10 = 15 cents;
so, there are 345/15 = 23 groups consisting of one nickel and one dime.


From it, we conclude that the initial collection is  23 dimes  and  23 + 20 = 43 nickels.


<U>ANSWER</U>.  23 dimes and 43 nickels.


<U>CHECK</U>.  23*10 + 43*5 = 445 cents = $4.45.    ! correct !
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Solved.