Question 1204424

Find angle {{{A}}} when

{{{a = 23}}}
{{{b = 9}}}
{{{B = 28}}}°

 use the Law of Sines:

{{{a/sin(A)=b/sin(B)}}}

{{{23/sin(A)=9/sin(28)}}}

{{{23sin(28)=9sin(A)}}}

{{{sin(A)=(23sin(28))/9}}}

{{{sin(A)=1.199760660452832}}}

{{{A=sin^-1(1.199760660452832)}}}

{{{A=1.570796326794897 -0.6220015679413891*i}}}

there is no real solution

For ASS (SSA) theorem {{{sin(B) > b/a}}} so there are{{{ no}}} solutions and {{{no}}}{{{ triangle}}}!


answer: IMPOSSIBLE