Question 1204411
.


Use the rule of divisibility by 9:


<pre>
    The remainder of divisibility by 9 of the number N is the same,
    as the remainder of the sum of digits of the number N when divided by 9.
</pre>

<pre>
The number  274563358  has the sum of its digits  2+7+4+5+6+3+3+5+8 = 43.


So, the number 274563358  itself,  when divided by 9, gives the same remainder 
as the sum of its digits 43 divided by 9, i.e. 43 mod 9 = 7.


Hence, {{{274563358^5}}} when divided by 9 gives the same remainder as the number {{{7^5}}} = 16807 when divided by 9.


Again, the number 16807 has the sum of the digits  1+6+8+7 = 22.

Therefore, the answer to the problem's question is 22 mod 9 = 4.
</pre>

Solved.


-----------------


On the rule of divisibility by &nbsp;9 &nbsp;see the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/divisibility/lessons/Divisibility-by-9-rule.lesson>Divisibility by 9 rule</A>  

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/divisibility/lessons/Restore-the-omitted-digit-in-a-number-in-a-way-the-number-is-divisible-by-9.lesson>Restore the omitted digit in a number in a way that the number is divisible by 9</A>

in this site.