Question 1204372
If the second and fifth terms of an G.P are 6 and 48 respectively, find the 10th term of the G.P

nth. term of GP =  an = ar^(n-1)

a5 = 48 - a^(5-1)
-> 48 = ar^4---------------(1)

Similarly
a2 = 6= a^(2-1)

ar =6------------------------(2)
divide (2) by(1)

48/6 = ar^4/ar
r^3=8
r=2

ar =6

but r=2
2a=6
a=3

a10 = ar^9

a10 = 3*2*9 =1536

10th term of the geometric progression is 1536.