Question 115512
b)


From this graph, we can see the vertex is (0,6). So this means h=0 and k=6


So we'll follow the same routine as we did for part a)


{{{y=(x-h)^2+k}}} Start with the general equation in vertex form. In this case, a=1



{{{y=(x-0)^2+6}}} Plug in h=0 and k=6.



{{{y=x^2+6}}} Rewrite {{{x-0}}} as {{{x}}}.




So the equation of the parabola that has been shifted 6 units up is {{{y=x^2+6}}}