Question 1204349


{{{f(x) = -3x^2 + x + 1}}}


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

in your case {{{a=-3}}}, {{{b=1}}}, and {{{c=1}}}


{{{x = (-1 +- sqrt( 1^2-4*(-3)*1 ))/(2*(-3)) }}}


{{{x = (-1 +- sqrt( 1+12 ))/(-6) }}}

{{{x = (-1 +- sqrt( 13 ))/(-6) }}}


solutions:


{{{x =  1/6 +sqrt(13)/6 }}}

or

{{{x =  1/6 - sqrt(13)/6 }}}