Question 1204334
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In a lottery game, a player picks six numbers from 1 to 48. If 5 of the 6 numbers matches those drawn, 
the player wins the second prize. What is the probability of winning this prize?
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        Similar problem (a TWIN) was solved at this forum several years ago: see the link

        https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1061914.html


        So, I will follow this solution, by modifying it, where it is needed.



<pre>
           <U>Solution</U>


# of groups of 6 numbers:: 48C6
# of winning groups of 6 numbers:: 1
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# of sets of 5 numbers in the winning set:: 6C5 = 6.
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P(getting a winning set of 5) = (6C5)/(48C6) = 6/12271512 = 4.88937E-07.    <U>ANSWER</U>
</pre>

Solved.