Question 1204301


How much pure acid should be mixed with 4 gallons of a 60%  acid solution in order to get  80% acid​ solution?

Pure acid 100%
Let quantity to be added be x gallons to get 80% acid

available acid 60%  4 gallons

Required 80% acid . Volume after mixing will be (4+x) gallons

100*x+60*4= (x+4) *80

100x+240 = 80x+320

20x = 80

x=4 

 mix 4 gallons of pure acid with the 4 gallons of the 60% acid solution to get  80% acid solution.