Question 115484
I'VE SEEN PROBLEMS SIMILAR TO THIS IN THE PAST AND THEY USUALLY SPECIFY THE HEIGHT OF THE BOX.

Volume(V) of a box=Length(L) times Width(W) times Height(H) or V=LWH
Area(A) of the bottom=Length(L) times Width(W) or A=LW

V=LWH=(x^2+5x+6)(x+5); x^2+5x+6=(x+3)(x+2), So:
LWH=AH=(x+3)(x+2)(x+5)

Now, if H=(x+3), then A=(x+2)(x+5) or x^2+7x+10
if H=(x+2), then A=(x+3)(x+5)=x^2+8x+15
if H=(x+5), then A=x^2+5x+6

Hope this helps---ptaylor