Question 1204211
There is a right-angled triangle (height=4x, base=x) and a rectangle (length=5x-2, width=x-1). all measurements are in centimeters. the area of the rectangle is greater than the area of the triangle. find the set of possible values of x. step-by-step explanation needed please


There is a right-angled triangle (height=4x, base=x)

Area of triangle 1/2 * 2x*x = 2x^2

 a rectangle (length=5x-2, width=x-1).

Area of rectangle = L*W =(5x-2)(x-1)
= 5x^2-7x+2

5x^2-7x+2 >2x^2

3x^2-7x+2>0

3x^2-6x-x+2>0

3x(x-2)-1(x-2)>0

(x-2)(3x-1)>0

either (x-2)>0 or 3x-1>0

x>2 or x>1/3

x>2