Question 1204192
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At least 2 defective --> not either 0 or 1 defective.<br>
P(0 defective) = {{{(0.95)^75}}} = .0213437 to several decimal places<br>
P(1 defective) = {{{(C(75,1))((0.95)^74)((0.5)^1)}}} = .0842516<br>
P(0 or 1 defective) = .0213437 + .0842516 = .1055953<br>
P(at least 2 defective) = 1-.1055953 = .8944047<br>
ANSWER: a) 0.8944<br>