Question 1204191
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According to Vieta's theorem, these two numbers are the roots of the quadratic equation

    x^2 + 4x + 5 = 0.


From here, it is easy to find these numbers

    (x^2 + 4x + 4) + 1 = 0

     {{{(x+2)^2}}} = -1

     x + 2 = {{{sqrt(-1)}}} = +/- i

     x = -2 +/- i,

where "i" is the imaginary unit.
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