<PRE><B>Question 1204189</B>
The product of the first and third of three negative consecutive integers is 59 more than 4 times the second integer. Find the integers.

Let the integers be  x-1 , x , x+1

(x-1)(x+1)=59+4x

x^2-1-4x =59

x^2-4x-60=0

x^2-10x +6x-60=0

x(x-10)+6(x-10)=0

(x-10)(x+6)=0

x=-6 or 10

the numbers are negative

so x=-6

the integers are -7,-6,-5 as per given condition

CHECK
(x-1)(x+1)=59+4x

(-7)(-5) = 59 -4*(-6)

35 = 35



</PRE>