Question 1204178
<pre>
12 = 1/32 * x ^ (3/2) - 4

I'd presume you're seeking the value of x. Is it that difficult to say so?

          {{{matrix(4,3, 12, "=", matrix(2,1, " ", (1/32)x^(3/2) - 4), 12, "=", x^(3/2)/32 - 4, 12 + 4, "=", matrix(2,1, " ", x^(3/2)/32), 16, "=", matrix(2,1, " ", x^(3/2)/32))}}}
          {{{matrix(1,3, matrix(2,1, " ", x^(3/2)), "=", 32(16))}}} ------ Cross-multiplying
          {{{matrix(2,3, matrix(2,1, " ", x^(3/2)), "=", (2^5)(2^4), matrix(2,1, " ", x^(3/2)), "=", 2^9)}}} 
   {{{matrix(1,3, matrix(2,1, " ", x^((3/2)(2/3))), "=",2^(9(2/3)))}}} ------ Multiplying exponents by {{{2/3}}}
{{{matrix(1,3, matrix(2,1, " ", x^((cross(3)/cross(2))(cross(2)/cross(3)))), "=",2^(3cross(9)(2/cross(3))))}}} 
             <font color = red><font size = 4><b>x</font></font></b><font size = 4><b> = 2<sup>6</sup> = <font color = red><font size = 4><b>64</font></font></b></pre>