Question 1204174
The length of a rectangle is twice its width. If the width is reduced by 1 cm and the length is also reduced by 2 cm, the area will be 15cm².
Find the dimensions of the original rectangle.

Let width be x cm
Length will be 2x cm .

 (I have reduced length also by 1 and not 2)

 If the width is reduced by 1 cm and the length is also reduced by 1 cm, the area will be 15cm².

(x-1)(2x-1)=15

2x^2-x-2x+1=15

2x^2-3x -14=0

2x^2-7x+4x-14=0

x(2x-7)+2(2x-7)=0

(2x-7)(x+2)=0

x= 7/2 0r -2

-2 not possible

x=3.5 = width

length = 2x = 7 

Area = 7*3.5 = 24.5 cm^2

So, the dimensions of the original rectangle are:
Width (w) = 3.5cm
Length (l) = 7 cm

Check

(7-1)(3.5-1)= 15