Question 1204159


We may use the formula for combinations to find how many different lottery tickets can be made with {{{5}}}  different numbers selected from{{{ 1 }}} to {{{51}}} : 

{{{C(n,r) =n / (r!(n-r)!)}}} 

{{{C(51,5) = 51! / (5! (51-5)!) = 51! / (5!46!) =2349060}}}