Question 1204128



 let shares ( ${{{2.00}}} per share ) be {{{x}}} and shares ( ${{{3.25}}} per share ) be {{{y}}}

if an  investor bought {{{300}}}  shares, we have

{{{x+y=300}}}...solve for {{{x}}}

{{{x=300-y}}}......eq.1


If the total cost was ${{{756.25}}}, we have

{{{2.00x+3.25y=756.25}}}....eq.2

substitute  {{{x}}} from eq.1

{{{2.00(300-y)+3.25y=756.25}}}

{{{600-2.00y+3.25y=756.25}}}

{{{1.25y=756.25-600}}}

{{{1.25y=156.25}}}

{{{y=156.25/1.25}}}

{{{y=15625/125}}}

{{{y=125}}}


go to eq.1 and substitute  {{{y}}} 

{{{x=300-125}}}......eq.1

{{{x=175}}}

check:

{{{175*2.00+125*3.25=756.25}}}