Question 1204069
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You have received several responses showing valid solutions.  They all use equations involving the reciprocals of A and C, because that is how the information is given.<br>
The algebra is easier if you set up the problem differently.<br>
2/7 of the reciprocal of A is 7/2 times A; 1/3 of the reciprocal of C is 3/1 times C.<br>
A, B, and C are consecutive natural numbers, and we are solving for B.  So A is B-1 and C is B+1.  Then we have<br>
{{{(7/2)(B-1)=3(B+1)}}}
{{{7(B-1)=6(B+1)}}}
{{{7B-7=6B+6}}}
{{{B=13}}}<br>
ANSWER: B = 13<br>