Question 1204069
<pre>
A, B and C are consecutive natural numbers. If 2/7 of the reciprocal of A is equal to ⅓ of the reciprocal of C, find B.​

Let B = B
Since A, B, C are natural consecutive numbers, then A = B - 1, and C = B + 1
We then get: {{{matrix(3,3, (2/7)(1/(B - 1)), "=", (1/3)(1/(B + 1)), 2/(7(B - 1)), "=", 1/(3(B + 1)), 2/(7B - 7), "=", 1/(3B + 3))}}}
                 2(3B + 3) = 7B - 7 ------ Cross-multiplying
                    6B + 6 = 7B - 7
                     6 + 7 = 7B- 6B
                       <font color = red><font size = 4><b>13 = B</font></font></b></pre>