Question 1204075
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Working the problem in 2 dimensions, we have an upward-opening parabola with vertex (0,0), with two other points at (-24,6) and (24,6).<br>
The problem asks for where the receiver should be placed, which is at the focus of the parabola.  Using the standard notation with p as the distance from the vertex to the focus, the equation of the parabola is<br>
{{{y=(1/(4p))x^2}}}<br>
Determine p using (x,y)=(24,6).<br>
{{{6=(1/(4p))(24^2)}}}
{{{1/(4p)=6/(24^2)=1/96}}}
{{{4p=96}}}
{{{p=24}}}<br>
p, the distance from the vertex to the focus, is 24 feet, so the focus is at (0,24).<br>
ANSWER: 24 feet above the vertex<br>