Question 1204078
First, plot the vertex and the focus to understand the orientation of the parabola.

In this case, we have a parabola that opens to the right. The form of the equation for this type of parabola is:

{{{4p(x-h)=(y-k)^2}}} 
 
where the vertex is at  ( {{{h}}} , {{{k}}} ) and {{{ p }}} is the distance from the vertex to the focus.

For the given problem, we have vertex ({{{-3}}} ,{{{2}}} ) and focus ({{{2}}} ,{{{2}}} )

 ( {{{h}}} , {{{k}}} )=({{{-3}}} ,{{{2}}} )  and the distance from the vertex to the focus  {{{p=5}}} 

 . Therefore, the required equation is:

{{{4*5(x-(-3))=(y-2)^2}}} 

{{{20(x+3)=(y-2)^2}}} 



{{{ drawing( 600, 600, -10, 10, -10, 10,
circle(-3,2,.12), circle(2,2,.12),locate(2,2,F(2,2)),locate(-3,2,V(-3,2)),

graph( 600, 600, -10, 10, -10, 10, 2(1 -sqrt(5)*sqrt(x + 3)), 2(sqrt(5)*sqrt(x + 3) + 1)) )}}}