Question 1204080
if ray QS bisects angle RQT, and if angle RQS=7x+7 and angle RQT=9x+54, find angle SQT. 

 Angle RQS  + angle SQT = angle RQT

Angle SQT = Angle RQT - Angle RQS = Angle SQT

9x+54 -(7x+7)= Angle SQT

9x +54 -7x-7 =  Angle SQT

2x +47 = Angle SQT

Since ray QS bisects angle RQT Angle RQS  = angle SQT 

7x+7 = 2x+47

5x = 40

x =8
Angle SQT = 2x+47 =63 deg