Question 1204062



The number of trials is {{{n = 6}}}
The probability of success is {{{ p = 0.2}}}

the number of successes in a fixed number of trials is {{{k = 4}}}

The probability that the random variable has exactly {{{4}}} successes is


{{{P(k=4)=C(n,k)*p^k*(1-p)^(n-k)}}}

{{{P(k=4)=C(6,4)*0.2^4*(1-0.2)^(6-4)}}}

{{{P(k=4)=C(6,4)*0.2^4*(0.8)^2}}}

{{{P(k=4)=15*0.0016*0.64}}}

{{{P(k=4)=0.015360}}}